if the perpendicular bisector of chord AB of circle PXAQBY intersects the circle at P and Q prove that arc pxa is congruent to arc pyb
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if the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA is congruent to arc PYB. Let O be the centre of the circle. Given: Chord AB, PQ bisects AB and PQ ⊥ AB. Thus, ΔPMA and ΔPMB are congruent.
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