If the perpendicular distance of a point P from the x-axis is 7 units and the foot of the perpendicular lies
on the negative direction of x-axis, then the point P has:
a) y-coordinate = 7 or –7 only
b) y-coordinate = 7 only
c) y-coordinate = –7 only
d) x-coordinate = –7
Answers
Given : The perpendicular distance of a point P from the x-axis is 7 units and the foot of the perpendicular lies on the negative direction of x-axis, then the point P has:
To Find : the point P has
a) y-coordinate = 7 or –7 only
b) y-coordinate = 7 only
c) y-coordinate = –7 only
d) x-coordinate = –7
Solution:
The perpendicular distance of a point P from the x-axis is 7 units
A line y = k has a distance of | k | from x axis
Distance is 7 units
Hence | k | = 7
=> k = ± 7
Hence y = ± 7
Point P = ( x , ± 7)
Hence y-coordinate = 7 or –7 only
Additional Info :
Perpendicular lies on the negative direction of x-axis Hence x coordinate of point P must be negative
point P has y-coordinate = 7 or –7 only
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Answer:
The perpendicular distance of a point P from
the x-axis is 7 units
A line y = k has a distance of Ikl from x
axis
Distance is 7 units
Hence |k| = 7
=> k = ± 7
Hence y = plus/minus 7
Point P = (x, plus/minus 7)
Hence y-coordinate = 7 or -7 only.