If the pH=9 for a solution of KOH(aq), what is the concentration of HO−?
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hello mate..
we can find it by relationship of pH and poH.
pH = 14 - log (OH)
9 = 14 - log (OH)
log (OH) = 5
take antilog u will get
oH = 1× 10^-5 or 0.00001
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