IF the pH of the solution ia 4 ·5, what is its pOH
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Answer:
Consider a solution with a pH =4.0. The [H+] of the solution would be 1.0×10−4M. Dividing Kw by this yields a [OH−] of 1.0×10−10M. Finally the pOH of the solution equals −log(1.0×10−10)=10.
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Answer:
-log(1.0×10-10)=10
Explanation:
Consider a solution with a pH =4.0. The [H+] of the solution would be 1.0×10−4M. Dividing Kw by this yields a [OH−] of 1.0×10−10M. Finally the pOH of the solution equals −log(1.0×10−10)=10.
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