Question

If the phase angle of the voltage coil of a directional relay is 50° the maximum torque

angle of the relay is​

Answer 1

Answer:

I think the answer is 50°

Answer 2

Given:

A direction relay

The phase angle of the voltage coil is $\phi=50 ^{\circ}$

To Find:

The maximum torque

Solution:

The formula of torque is

$T=K_{3} \times V \times I \times sin(\theta-\phi)$

For maximum torque

$\theta-\phi=90^{\circ}\\\tau-\phi=90^{\circ}\\\tau=90^{\circ}+\phi\\=90^{\circ}+50^{\circ}\\=140^{\circ}$

The maximum torque angle of the relay is $140^{\circ}$.