If the point (2,0) lines on the graph of the equation 5y=ax+10 find the value of a.
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Answer:
-5
Step-by-step explanation:
the common eqn for points on a graph is ax+by=c
over here if the eqn is rearranged, it will be ax-5y = -10
therefore, 5y = 2a+10
here x=2 and y=0 (substitute these values in the given qn
ax+10=5y
2a+10=5y
2a+10=0
2a = -10
a = -5
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