Question

If the point (2, 1) lies on the graph of the linear equation ax + 3y = 5, find the value of a

Answer 1

Answer:

Given equation is: 2y=ax−4.

It is also given that the point (1,2) lies on the graph of the equation.

⇒2(2)=a(1)−4

⇒a=4+4

⇒a=8

Now, the linear equation is: 2y=8x−4 or y=4x−2

Again, when y=0,x=

2

1

and

when x=0,y=−2

Therefore, the graph of the equation is as:

Answer 2

Answer: value of a is 1

Step-by-step explanation:

value of x= 2 and value of y=1

now , we put all the given values in given equation

⇒ a×2 + 3×1 = 5

⇒ 2a = 5 - 3

⇒ a = 2/2

⇒ a = 1