if the point (2,-2) lies on the graph of the linear equations 5x+ky=4, find x
Anonymous:
we have to find k
Answers
Answered by
21
5×2+k×(-2)= 4 after putting value from points
10 -2k= 4
-2k= 4-10= -6
k=6÷2
k=3
10 -2k= 4
-2k= 4-10= -6
k=6÷2
k=3
Answered by
10
Heyyy mate...
here is your answer...
given (2,-2)
X= 2 y= -2
equation, 5x+ky=4
5(2)+k(-2)=4
10-2k=4
-2k=4-10=-6
cancelling (-) both side
k= 6/2=3
i think in your question on the place of (find X) will be find K
hope it help you
here is your answer...
given (2,-2)
X= 2 y= -2
equation, 5x+ky=4
5(2)+k(-2)=4
10-2k=4
-2k=4-10=-6
cancelling (-) both side
k= 6/2=3
i think in your question on the place of (find X) will be find K
hope it help you
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