Math, asked by shravani05, 8 months ago

If the point (-2, 3) lies on the line 2(x -1) + 3y + k + 2 =0 then the value of k is ?
please answer with steps



Answers

Answered by illurib191044ee
0

Answer:

substitute the point in the equation you get the value of k.the value of k is -5

Answered by jitemath
1

Answer:

if the point (-2, 3) lies on the line 2(x -1) + 3y + k + 2 =0 then the value of k is ?

since (-2, 3) satisfied the equaiton 2(x -1) + 3y + k + 2 =0

hence

2(-2-1)+3*3+k+2=0

-6+9+k+2=0

5+k=0

k=-5

Answer: k=-5

Step-by-step explanation:

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