If the point (-2, 3) lies on the line 2(x -1) + 3y + k + 2 =0 then the value of k is ?
please answer with steps
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Answered by
0
Answer:
substitute the point in the equation you get the value of k.the value of k is -5
Answered by
1
Answer:
if the point (-2, 3) lies on the line 2(x -1) + 3y + k + 2 =0 then the value of k is ?
since (-2, 3) satisfied the equaiton 2(x -1) + 3y + k + 2 =0
hence
2(-2-1)+3*3+k+2=0
-6+9+k+2=0
5+k=0
k=-5
Answer: k=-5
Step-by-step explanation:
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