Question

If the point (2, α, β) lies on the plane which passes through the points (3, 4, 2) and (7, 0, 6) and is perpendicular to the plane 2x - 5y = 15 , then (2α - 3β) is equal to:
(A) 12 (B) 7
(C) 5 (D) 17

Answer 1

Answer:

If the point (2, α, β) lies on the plane which passes through the points (3, 4, 2) and (7, 0, 6) and is perpendicular to the plane 2x – 5y = 15, then 2α – 3β is equal to :-

a)5

b)17

c)12

d)7

Correct answer is option 'D'. Can you explain this answer?

JEE Question

Answer 2

Step-by-step explanation:

n1×n2= 4(5i+2j-3k),now we know 5,2 and -3 are the dr.s of the plain in which the points(2,alpha,beta) and 7,0,6 and (3,4,2)

so now the eqaution of the plane will be

5(x-7)+2(y-0)-3(z-6)=0 now substitue the value..

5x-35+2y-35+18

10+2alpha-3beta-17=0

2alpha -3 beta =7