Question

if the point (2k-3,2) lies on the graph of the equation 2x+3y+16=0,find the value of k​

Answer 1

Answer:

k = -4

Step-by-step explanation:

If (2k-3, 2) lies on the graph of the equation 2x+3y+16=0,

               x = 2k-3 and y = 2 satisfies the equation

⇒ 2(2k-3)+3(2)+16 = 0

⇒ 4k-6+6+16 = 0

⇒ 4k+16 = 0

⇒ 4k = -16

⇒ k = -4

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