Question

If the point (2k-3,k+2) is a solution of linear equation 2x+3y+15=0, then find the value of k .

Answer 1

Answer:

x=2k - 3 and y =k + 2 in equation ,we get

2(2k-3)+3(k+2)+15=0

4k-6+3k+6+15=0

7k+15=0

7k=-15=k=-15/7

ANSWER=15/7