If the point (2k-3,k+2 ) lie on the graph 2x+3y+15=0 find k
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hello friend your answer is here
(2k-3,k+2) lie on the graph 2x+3y+15 = 0
so this point satisfy the graph..
now put the point in the given equation
2(2k-3) + 3(k+2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
7k +15 = 0
7k = -15
k = -15/7
thanks ☺
(2k-3,k+2) lie on the graph 2x+3y+15 = 0
so this point satisfy the graph..
now put the point in the given equation
2(2k-3) + 3(k+2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
7k +15 = 0
7k = -15
k = -15/7
thanks ☺
sangeetkamal:
ok
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