if the point (2k-3,k+2 lies on graph of equation 2x+3y+15=0.find the value of k
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2x + 3y + 15 = 0
( 2k - 3 , k + 2) lies on the equation
Solve k:
When y = k + 2, x = 2k - 3
2(2k - 3) + 3(k + 2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
7k + 15 = 0
7k = -15
k = -15/7
Answer: k = -15/7
garry636:
hloo
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their no value of x qnd in equestion their is no value of (k)
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