Math, asked by garry636, 1 year ago

if the point (2k-3,k+2 lies on graph of equation 2x+3y+15=0.find the value of k

Answers

Answered by TooFree
57

2x + 3y + 15 = 0

( 2k - 3 , k + 2) lies on the equation


Solve k:

When y = k + 2, x = 2k - 3

2(2k - 3) + 3(k + 2) + 15 = 0

4k - 6 + 3k + 6 + 15 = 0

7k + 15 = 0

7k = -15

k = -15/7


Answer: k = -15/7



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Answered by loveme111
4
their no value of x qnd in equestion their is no value of (k)

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