Math, asked by yogithmadhu206, 3 months ago

if the point (2k -3 k + 2) lies on the graph of equation 2x + 3y+ 15 = 0 find the value of k​

Answers

Answered by Raftar62
0

Answer: K = 0.

Step-by-step explanation:

  \red{ \underline{given:} } \\  \orange{the \: equation \: of \: the \: line \: is \:2x + 3y+ 15 = 0 \: and \: the \: points \: of \: the \: line \: is \:(2k -3 ,k + 2).  }\\  \red{ \underline{concept:}}\\ \orange{ the \: points \: lies \: in \: the \: line \: sutisfy \: the \: equation \: of \: that \: line}  \\  \\  \orange{ \therefore{putting \: the \: points \: on \: the \: equation \: of \: the \: line.}} \\ \\   \green{2 \times (2k - 3) + 3 \times (k + 2) + 15 = 0.} \\  \\ \green{ \implies{4k - 6 + 3k + 6 = 0.}} \\  \\ \green{ \implies{7k  = 0.}} \\  \\  \green{ \implies{ \underline{k  = 0.}}}

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