Question

if the point (2k-3,k+2) lies on the graph of equations 2x+3y+15=0. and find K​

Answer 1

Answer:

K = $\frac{-15}{7}$

Step-by-step explanation:

If (2k-3,k+2), lies on line 2x + 3y + 15 = 0

x = 2k - 3

y = k + 2

Putting value of x and y

2(2k - 3) + 3(k + 2) + 15 = 0

4k - 6 + 3k + 6 = -15

7k = -15

k = $\frac{-15}{7}$

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Answer 2

Answer:

The answer will be -(15/7)

Step-by-step explanation:

Let put (2k-3,k+2) on the equation —

2 (2k-3) + 3 (k+2) + 15 = 0

=> 4k - 6 + 3k + 6 + 15 = 0

=> 7k + 15 = 0

=> k = -(15/7)

So, The value of k is -(15/7).