if the point (2k-3,k+2) lies on the graph of the equation 2x+3y find the value of k
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Answer:
hey mate here is ur ans
Step-by-step explanation:
at (2k-1,k+1)
2x+3y = 2(2k-1)+3(k+1)
= 4k-2+3k+3
= 7k-1
k= 2x+3y+1/7
hope it help u
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