Question

If the point (2k-3,K+2) lies
on the graph
of the equation
2x+3y- 14 = 0 find the
value of k.​

Answer 1

Answer:

k = 2

Step-by-step explanation:

(2k - 3, k + 2) ===> x = 2k - 3 and y = k + 2

2x + 3y - 14 = 0

2(2k - 3) + 3(k + 2) - 14 = 0

4k - 6 + 3k + 6 - 14 = 0

7k - 14 = 0 ===> k = 2