Question

If the point 2k-3,k+2 lies on the graph of the equation 2x+3y+15=0 find the value of k

Answer 1

k can has value ie -15/7

Answer 2

hi !
here's your answer.

(2k - 3) & (k + 2) lies on graph of the equation 2x + 3y + 15 = 0

So,

x = 2k - 3 & y = k + 2

Substitute the values of x & y in the given equation .

2x + 3y + 15 = 0

2(2k - 3) + 3(k + 2) + 15 = 0

4k - 6 + 3k + 6 + 15 = 0

4k + 3k + 15 =0

7k + 15 = 0
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k = -15 / 7
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hope this helps ! ! ! #