if the point (2k-3,k+2) lies on the graph of the equation 2x+3y+1520 Find the value of k
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Answer:
k=-152/7
Step-by-step explanation:
Putting values of x and y coordinates in the equation,
2(2k-3)+3(k+2)+152=0
4k-6+3k+6+152=0
7k=-152
k=-152/7
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