Question

If the point (2k-3,k+2) line on the graph of equation 2x+3y+15=0, find the value of k.

Answer 1

Step-by-step explanation:

Put the value of (2k-3,k+2) in eq. 2x+3y+15=0

2(2k-3)+3(k-2)+15=0

4k-6+3k-6+15=0

7k=-15+12

7k=-3

k=-3/7

k=-0.42

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