Question

If the point (3,1/3) lies on the graph of the equation 3y=ax-2, then find the value of ‘a’

Answer 1

Answer:

1

Step-by-step explanation:  

If the point lies on the graph of the equation, then it is a solution of the equation.  

So,  

3(1/3)=3a-2  

1=3a-2  

1+2=3a  

3=3a  

3/3=a  

1=a

Hope it helped :)

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Answer 2

Answer:

$a = 1$

Step-by-step explanation:

$(x, y) = (3, \frac{1}{3})$

$3y=ax-2$

If a point lies on a graph, it will satisfy its equation.

i.e. the point is a solution of the equation of the line.

Therefore,  $(3, \frac{1}{3} )$ is a solution of the equation $3y = ax-2$

$3(\frac{1}{3}) = a(3) - 2$

$1 = 3a -2$

$3a = 3$

$a = 1$

Any corrections or suggestions for improvement are welcome :)