IF THE POINT (3,4)LIE ON THE GRAPH OF THE EQUATION 3y=ax+7 find the value of a
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(x,y)= (3,4)
so the eqn becomes,
3y= ax+7
(3*4)=(a*3)+7
12=3a+7
12-7= 3a
3a=5
so a= 5/3
so the eqn becomes,
3y= ax+7
(3*4)=(a*3)+7
12=3a+7
12-7= 3a
3a=5
so a= 5/3
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