if the point (3,4) lie on the graph of the equation 3y=ax+7 find the value of a
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Heya
Given point =>
(3, 4)
So, x = 3 and y = 4
Given equation =>
3y = ax + 7
Substitute the value of x and y.
We get,
3(4) = a(3) + 7
12 = 3a + 7
12 - 7 = 3a
3a = 5
a = 5/3
Hope this helps.
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