If the point (3, 4) lie on the graph of the linear equation 3y = kx + 6, then find
the value of k.
Answers
Answered by
7
value of k = 2.................
Answered by
2
Answer:
Since, the point (x = 3, y = 4) lies on the equation 3y = kx + 7
then the equation will be , satisfied by the point.
Now, put x = 3 and y = 4 in given equation, we get
3(4) = k (3)+7
⇒ 12 = 3k+7
⇒ 3k = 12 – 7
⇒ 3k = 5
Hence, the value of k is 5/3.
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