Math, asked by bhullarsukhleen90, 7 months ago

if the point (-3,-4)lies on a graph of equation 3y=ax+9 ,then find the value of a​

Answers

Answered by cknsr05
0

Answer:

a=7

Step-by-step explanation:

(-3,-4)

x= -3,y= -4

3y=ax+9

=> 3(-4)=a(-3)+9

=> -12= -3a+9

=>-3a= -12+(-9)

=>-3a= -21

=> a= -21/-3

=> a=7

Answered by nikhiljsh2004
0

Answer: 7

Step-by-step explanation:

the equation is 3y=ax+9

in (-3,-4); x=-3 & y=-4

now, put values of x and y in the given equation

3y=3*(-4)

ax+9=a*(-3)+9

now 3y=ax+9 can be written as:

-12= -3a+9

-12-9= -3a

-21= -3a

therefore, a=7

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