if the point (3,4) lies on the graph of 3y=ax+7, then find the value of a²- a²
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Answered by
0
Answer:
The answer is zero as the value of a is the same therefore a square minus a square will be zero
Answered by
2
Answer:t
5/16
Step-by-step explanation:
3y=ax+7
12 = 4a + 7
4a = 5
a = 5/4
a²- a² = a(a-1) = 5/4×1/4 = 5/16
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