if the point (3;4) lies on the graph of the equation 3y=ax+7; find the value of a
Answers
Answered by
1285
if the point (3,4) lies on the given line, x=3 and y=4 will satisfy the given equation.
3y= ax+7
3(4)= a(3)+7
12 = 3a+7
12-7 = 3a
5= 3a
5/3 = a
3y= ax+7
3(4)= a(3)+7
12 = 3a+7
12-7 = 3a
5= 3a
5/3 = a
Answered by
6
According to the question;
point = (3, 4) where x = 3 and y = 4
equation = 3y=ax+7
a =?
Now;
put x = 3 and y = 4 in the equation = 3y=ax+7
3 (4) = a3 +7
12 = 3a +7
3a = 12 - 7
3a = 5
If the point (3;4) lies on the graph of the equation 3y=ax+7; then the value of
#SPJ2
Similar questions