Question

if the point (3;4) lies on the graph of the equation 3y=ax+7; find the value of a

Answer 1

if the point (3,4) lies on the given line, x=3 and y=4 will satisfy the given equation.

3y= ax+7
3(4)= a(3)+7
12 = 3a+7
12-7 = 3a
5= 3a
5/3 = a

Answer 2

According to the question;

point = (3, 4) where x = 3 and y = 4

equation =  3y=ax+7

a =?

Now;

put x = 3 and y = 4 in the equation =  3y=ax+7

3 (4) = a3 +7

12 = 3a +7

3a = 12 - 7

3a = 5

$a = \frac{5}{3}$

If the point (3;4) lies on the graph of the equation 3y=ax+7; then the value of  $a = \frac{5}{3}$

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