Math, asked by akku3650, 8 months ago

if the point (3, 4) lies on the graph of the equation 3y=ax+7, find the value of a​

Answers

Answered by MrJATINRAO
10

Answer:

A=-5/3

Step-by-step explanation:

Answered by Anonymous
28

Solution:

The given equation is 3y = ax+7

According to the question, x = 3 and y = 4

Now, Substituting the values of x and y in the equation 3y = ax+7,

We get,

(3×4) = (a×3)+7

⟹ 12 = 3a+7

⟹ 3a = 12–7

⟹ 3a = 5

⟹ a = 5/3

The value of a, if the point (3,4) lies on the graph of the equation 3y = ax+7 is 5/3.

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