if the point (3,4) lies on the graph of the equation 3y= ax+7, find the value of a.
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Answer:
3y= ax+7
3y-ax=7
3(4)-a(3)=7
12-3a=7
-3a=7-12
-3a=-5
a=-5/-3
a=5/3
PROVE:
3(4)=5/3×3+7
12=5+7
12=12
Hope it will help you!!
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