Question

if the point (3,4) lies on the graph of the equation 3y= ax+7, find the value of a.​

Answer 1

Answer:

3y= ax+7

3y-ax=7

3(4)-a(3)=7

12-3a=7

-3a=7-12

-3a=-5

a=-5/-3

a=5/3

PROVE:

3(4)=5/3×3+7

12=5+7

12=12

Hope it will help you!!