If the point (3, 4) lies on the graph of the equation 3y=ax+7, find the value
of a.
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Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7⇒ 12 = 3a+7
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7⇒ 12 = 3a+7⇒ 3a = 12 – 7
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7⇒ 12 = 3a+7⇒ 3a = 12 – 7⇒ 3a = 5
Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7⇒ 12 = 3a+7⇒ 3a = 12 – 7⇒ 3a = 5Hence, the value of a is 5/3.
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