Question

If the point (3, 4) lies on the graph of the equation 3y
= ax + 7, find the value of a​

Answer 1

Answer:

(3,4)=(x,y).....x=3,y=4

3y=ax+7

3(4)=a(3)+7......(x=3 y=4)

12=3a+7

12-7=3a

5=3a

5/3=a

a=5/3

Answer 2

Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.

Now, put x = 3 and y = 4 in given equation, we get

3(4) = a (3)+7

⇒ 12 = 3a+7

⇒ 3a = 12 – 7

⇒ 3a = 5

Hence, the value of a is 5/3.