Question

If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

Answer 1

Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.

Now, put x = 3 and y = 4 in given equation, we get

3(4) = a (3)+7

⇒ 12 = 3a+7

⇒ 3a = 12 – 7

⇒ 3a = 5

Hence, the value of a is 5/3.

Answer 2

Answer:

Given,

3y = ax + 7

Find,

the value of a

Step-by-step explanation:

The equation of the given line is 3y = ax + 7

∵ (3, 4) lies on the given line.

∴ It must satisfy the equation 3y = ax + 7

We have,

(3, 4) => x = 3 and y = 4.

Putting these values in given equation,

we get,

3 * 4 = a * 3 + 7

=> 12 = 3a + 7

=> 3a = 12 – 7 = 5 => a = 5/3

Thus,

the required value of a is 5/3