If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.
Answers
Answered by
1
Answer:
3(4) = a(3) + 7
12 = 3a + 7
12 - 7 = 3a
5 = 3a
a = 5/3
Answered by
1
Answer:
If (3,4) lies in the equation 3y=ax+7, then the must satisfy the equation of the line.
Thus, 3(4)=a(3)+7
⇒12=3a+7
⇒a=
3
5
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