Question

:If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.

Answer 1

Answer:

Step-by-step explanation:

The given equation is

3y = ax + 7

According to the question, x = 3 and y = 4

Now, Substituting the values of x and y in the equation 3y = ax + 7,

We get,

(3×4) = (ax3) + 7

⇒ 12 = 3a+7

⇒ 3a = 12–7

⇒ 3a = 5

⇒ a = 5/3

The value of a, if the point (3, 4) lies on the graph of the equation 3y = ax + 7 is 5/3.

Answer 2

Answer:

$the \: point \: are : (3,4) \\ 3y = ax + 7 \\ \color{blue} \underline{put \: the \: point \: in \: equation} \\ 3 \times 4 = a \times 3 + 7 \\ 12 = 3a + 7 \\ 3a = 12 - 7 \\ 3a = 5 \\ \boxed{a = \frac{5}{3} } \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$