If the point (3,4) lies on the graph of the equation 3y=ax+7 then find the value of a
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Answered by
30
Heya!!
Here is your answer:
point is (3,4)
So, x= 3 and y=a
equation==> 3y=ax+7
Put value of x and y in equation:
3y=ax+7
3(4) = a(3) +7
12= 3a+7
3a= 5
a= 5/3
Here is your answer:
point is (3,4)
So, x= 3 and y=a
equation==> 3y=ax+7
Put value of x and y in equation:
3y=ax+7
3(4) = a(3) +7
12= 3a+7
3a= 5
a= 5/3
Answered by
10
here is your answer
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