Question

if the point (3,4)lies on the graph of the equation 3y-ax+7.find the value of a.

Answer 1

Answer:

Step-by-step explanation:

if the point (3,4) lies on the given line, x=3 and y=4 will satisfy the given equation.

3y= ax+7

3(4)= a(3)+7

12 = 3a+7

12-7 = 3a

5= 3a

5/3 = a

Answer 2

$\huge\colorbox{Limegreen}{Answer!}$

$\qquad \tt \: \: \: \: \: \qquad \: x = 3 \\ \\ \qquad \tt \: \: \: \: \qquad \: y = 4 \\ \\ \implies \sf \: 3y = ax + 7 \\ \\ \\ \implies \sf \: 3(4) = a(3) + 7 \\ \\ \\ \implies \sf \: 12 = 3a + 7 \\ \\ \\ \implies \sf \: 3a = 12 - 7 \\ \\ \\ \implies \sf \: 3a = 5 \\ \\ \\ \implies \sf \blue{a = \frac{5}{3} } \\ \\ \\ \therefore \rm \: \: Value \: \: of \: \: a \: \: is \: \: \frac{5}{3}$

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