if the point 3, 4 on the graph of the equation 3Y is equal to aX + 7 find the value of a
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Answer:
If the point (3,4) lies on the given line, x=3 and y=4 will satisfy the given equation.
3y= ax+7
3(4)= a(3)+7
12 = 3a+7
12-7 = 3a
5= 3a
5/3 = a
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Given, x = 3 &
Y = 4
3y = ax +7
3×4= a × 3 + 7
12 = 3a +7
12-7= 3a
5 = 3a
a = 5/3........
The value of a is 5/3 .....
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