Question

If the point (3, ⅓) lies on the graph of the equation 3y=ax - 2, then find the value of “a”
Please help me with this question I need it for my exam tomorrow I need with format ​

Answer 1

Answer:

$a = 1$

Step-by-step explanation:

$(x, y) = (3, \frac{1}{3})$

$3y = ax - 2$

If a point lies on a line, it will satisfy the equation of that line

i.e. the point is a solution of the equation of the line.

∴ $(3, \frac{1}{3})$ is solution of the equation $3y = ax -2$.

$3 (\frac{1}{3}) = a(3) - 2$

$1 = 3a - 2$

$3a = 3$

$a = 1$

Any corrections or suggestions for improvement are welcome :)