Question

If the point (5, 2) bisects the intercept of a line between the axes, then its equation is-

Answer 1

Answer:

2x + 5y = 20 is the required equation of the line.

Step-by-step explanation:

Hi,

Let the x-intercept of the line be 'a'

Let the y-intercept of the line be 'b'

Since, x-intercept is a, line passes through A(a, 0)

Since, y-intercept is b, line passes through B(0, b)

Midpoint of AB = (5, 2)

(a/2, b/2) = (5, 2)

=> a = 10 and b = 4

Thus coordinates of A(10, 0) and B(0, 4), x-intercept is 10 and y-intercept is 4.

Equation of line whose x-intercept is 'a' and y-intercept  is 'b' given  by

x/a + y/b = 1

=> x/10 + y/4 = 1

=> 2x + 5y = 20 is the required equation of the line.

Hope, it helps !