Math, asked by supriyasingh6785, 10 months ago

If the point (5,2) lies on the graph of the linear equation kx 5y= 10k find k

Answers

Answered by idris78

41

Step-by-step explanation:

k(5)+ 5(2)=10k

5k+10=10k

10=10k-5k

10=5k

k=10/5

k=2

Answered by geetikamrhr

4

k(5)+5(2)=10k

=5k+10=10k

=10=10k-5k

=10=5k

=k=10/5

=k=2

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