Question

If the point(5,4) lies on the graph of the equation 3y=ax+7,find the value of a.
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Answer 1

Solution -

It is given that, point (5, 4) lies on the graph of the equation 3y = ax + 7.

Since, the point is also the solution of the given equation. It also satisfy the equation.

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Therefore,

• x = 5
• y = 4

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Putting values of x and y in the equation

→ 3y = ax + 7

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→ 3(4) = a(5) + 7

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→ 12 = 5a + 7

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→ 5a = 12 - 7

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→ 5a = 5

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→ a = 5/5

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→ a = 1

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Hence,

• The value of a is 1.

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Answer 2

Given :

• Points = (5,4)
• Equation = 3y=ax+7

To Find :

• Value of a

Solution :

If (5,4) lies on the graph of the equation 3y=ax+7

Then the must statisfy the equation of the line.

So Let's take (5,4) as,

• x = 5
• y = 4

Now put x = 5 and y = 4 in the given equation ( 3y=ax+7 )

$\tt \longrightarrow \: 3 \: y \: = \: a \: x \: + \: 7 \\ \\ \tt \longrightarrow \: 3 \: (4) \: = \: a \: (5) \: + \: 7 \\ \\ \tt \longrightarrow12 \: = \: 5a \: + \: 7 \\ \\ \tt \longrightarrow \: 5 a \: = \: 12 \: - \: 7 \\ \\ \tt \longrightarrow \: 5a \: = \: 5 \\ \\ \tt \longrightarrow \: a \: = \: \frac{5}{5} \\ \\ \tt \longrightarrow \: a \: = \: 1$

•°• The value of a = 1