Question

If the point A (0,2) is equidistant from the point (3,P) and C ( P,5) find the value of P.

Answer 1

after squaring AB andAC we use distance formula to solve this type of problem

Answer 2

Answer:

AB = AC

⇒AB =√(3-0)²+(p-2)² and AC =√(p-0)² + (5-2)²

⇒(3-0)² + (p-2)² =(p-0)² + (5-2)²

⇒9 + p² + 4 - 4p = p² + 9

⇒9 - 9 +p² - p² +4 -4p =0

⇒4 - 4p=0

⇒-4p =-4

⇒p = 1

so p=1 is the answer.