Question

If the point A (0,2) is equidistant
from the point B(8,-2) and C(P,5) Find the value of P also find the length of AB
​

Answer 1

Answer:

AB=AC

$\sqrt{ {(0 - 8)}^{2} } + {(2 - ( - 2))}^{2} = \sqrt{ {(0 - p)}^{2} } + {(2 - 5)}^{2}$

$\sqrt{ {8}^{2} } + {4}^{2} = \sqrt{} {p}^{2} + {3}^{2}$

root get cancel

${8}^{2} + {4}^{2} = {p}^{2} + {3}^{2}$

$64 + 16 = {p}^{2} + 9$

80=p² +9

p² = 80-9

p²=71

p=√71

distance AB

80 square unit

Step-by-step explanation:

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