If the point A (-1, 3), B(1,-1) and ( (5, 1) are the
veselices of a AABC. Find the length of the median
through the vertex d. also find the coordinate of the
controid of this triangle
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come ordinates of median AD from vertex a on BC is
x co ordinate = 1+5/2 =6/2 =3
y co ordinate -1+1/2=0
length of median AD =[(-1+3)^2 +(3-0)^2]^1/2 = 5
coordinate of centroid of triangle ABC are
x coordinate =-1+1+5 /3 =5/3
y coordinate = 3+(-1) +1 /3 =3/3= 1
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