If the point (a, 2) is on the line 2x – 3y + 8 = 0 then find the value of a.
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Given equation of line is 2x−3y+8=0⋯(1)
Also given that (a,2) lies on the line
So (a,2) must satisfy the equation (1)
⟹2(a)−3(2)+8=0
⟹2a−6+8=0
⟹2a=−2
⟹a=−1
The value of a is −1
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