If the point (a,2) lies on the graph of the linear equation 2x-3y+8=0, find the value of a.
Answers
Answered by
2
Answer:
2x-3y+8=0
x=a,y=2
therefore,
2(a)-3(2)+8=0
2a-6+8=0
2a+2=0
2a=0-2
2a= -2
a-2/2
a= -1
Step-by-step explanation:
we have point of x-axis and y-axis
In linear equation we have to substitute values of x and y
by solving step wise equation
we get value of 'a'
Answered by
0
Answer:
-1 is the correct answer
Step-by-step explanation:
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