Math, asked by venkatche7570, 9 months ago

If the point (a,2) lies on the graph of the linear equation 2x-3y+8=0, find the value of a.

Answers

Answered by najiyakhoja
2

Answer:

2x-3y+8=0

x=a,y=2

therefore,

2(a)-3(2)+8=0

2a-6+8=0

2a+2=0

2a=0-2

2a= -2

a-2/2

a= -1

Step-by-step explanation:

we have point of x-axis and y-axis

In linear equation we have to substitute values of x and y

by solving step wise equation

we get value of 'a'

Answered by sckhan23
0

Answer:

-1 is the correct answer

Step-by-step explanation:

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