if the point A (3,5) and B (4,4)lies on the graph of line ax+by=7 find the value of a
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x = 3, y = 5
so, 3a + 5b = 7........... (i) equation
x = 1, y = 4
a+4b = 7
a = 7-4b ..................(ii) equation
now put the value of (a) from 2nd equation in 1st equation
==> 3(7 - 4b) + 5b = 7
==> 21 - 12b + 5b = 7
==> -12b + 5b = 7 - 21
==> - 7b = - 14
==> 7b = 14
==> b = 14/7
==> b = 2
now put the value of (b) in 2nd equation
==> a = 7 - 4(2)
==> a = 7 - 8
==> a = -1
so, the value of a is -1
so, 3a + 5b = 7........... (i) equation
x = 1, y = 4
a+4b = 7
a = 7-4b ..................(ii) equation
now put the value of (a) from 2nd equation in 1st equation
==> 3(7 - 4b) + 5b = 7
==> 21 - 12b + 5b = 7
==> -12b + 5b = 7 - 21
==> - 7b = - 14
==> 7b = 14
==> b = 14/7
==> b = 2
now put the value of (b) in 2nd equation
==> a = 7 - 4(2)
==> a = 7 - 8
==> a = -1
so, the value of a is -1
Ankit1234:
i hope it helps
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