Question

If the point (a-5, 2a-9) lies on the graph of the equation 2x+3y+13=0, find the value of a

Answer 1

Answer:

given point is(a-5,2a-9)

so that x=a-5 ,y=2a-9

given equation is 2x+3y+13=0

put value of x and y in given equation

2(a-5)+3(2a-9)+13=0

2a-10+6a-27+13=0

2a+6a-10-27+13=0

8a-37+13=0

8a- 24=0

8a=24

a=24/8

a=3

Step-by-step explanation:

hope it helps