Question

If the point A (7.b) is the vertex of an isosceles triangle ABC with base BC
where B = (2, 4) and C (6.10), then what is 7
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Answer 1

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Answer 2

using distance formula

(7-2)^2+(b-4)^2=(7-6)^2+(b-10)^2

25 + b^2+16-8b=1 +b^2 + 100 -20b

41 -8b= 101-20b

12b= 60

b =5

so b is 5....